CompSciWeek5
From Predictive Chemistry
Revision as of 10:04, 29 September 2014 by David M. Rogers (talk | contribs)
Reading:
- Beginning Python, Chapters 7-8 and 16 (on Testing)
- Bioinformatics Code Design
Class 1 and 2: Code walkthrough
- Structuring a list min/max problem over multiple timescales
- Building and using a structured nearest neighbor graph
Example Codes
List Min/Max
See CompSciWeek1.
Using Graphs
<source lang="python">
- !/usr/bin/env python
from numpy import array, sum, reshape
- input - list of names
- - (3n)x 3 coordinate array
- output - Graph G
def make_G(names, x):
assert x.shape[0]%3 == 0 assert x.shape[1] == 3 assert len(names) == len(x)
print x.shape n = len(x)/3 G = {} D2 = sum((reshape(x, (1,3*n,3)) - reshape(x, (3*n,1,3)))**2, -1) print D2 # add bonds to G! for i,n in enumerate(names): print i,n G[i] = set() if n != 'O': continue for j,m in enumerate(names): print j,m if m != 'H': continue # all O-H distances, 1 at a time if D2[i,j] < 1.1: G[i].add(j) G[j].add(i) # Question for class: why does this cause an error? return G
- input - list of names (1 O per 2 H-s)
- - graph from atom number to atom numbers
- output - list of atom numbers ordered O, H, H, O, H, H, ...
def outp_graph(names, G):
out = [] for i,n in enumerate(names): if n != "O": continue out.append(i) # 'O' number bonds = G[i] assert len(bonds) == 2, "Bad number (%d) of O-bonds."%(len(bonds))
for j in bonds: # 'H' numbers out.append(j) return out
names = ['H', 'O', 'H', 'H', 'H', 'O'] x = array([[1,0,0],[0,0,0],[-1,0,0]]) G = make_G(names[:3], x) print G
- G = {0:{1}, 1:{0,4, 1}, 2:{5}, 3:{5}, 4:{1}, 5:{2,3} }
- l = outp_graph(names, G)
- print l
</source>